7x^2+42x-360=0

Solution for 7x^2+42x-360=0 equation:

7x^2+42x-360=0

a = 7; b = 42; c = -360;
Δ = b2-4ac
Δ = 422-4·7·(-360)
Δ = 11844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11844}=\sqrt{36*329}=\sqrt{36}*\sqrt{329}=6\sqrt{329}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6\sqrt{329}}{2*7}=\frac{-42-6\sqrt{329}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6\sqrt{329}}{2*7}=\frac{-42+6\sqrt{329}}{14}
$